PLEEASE PEALSE PLEASE HELP, 40 POINTS

FInd the roots of the equation 6a^2-3. If 6a=0

3 (a+1) (a-1)

STEP

1

:

Equation at the end of step 1

 3a2 -  3

STEP

2

:

STEP

3

:

Pulling out like terms

3.1     Pull out like factors :

  3a2 - 3  =   3 • (a2 - 1)

Trying to factor as a Difference of Squares:

3.2      Factoring:  a2 - 1

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 1 is the square of 1

Check :  a2  is the square of  a1

Factorization is :       (a + 1)  •  (a - 1)

Final result :

 3 • (a + 1) • (a - 1)

Step-by-step explanation:

i need a diagram

step-by-step explanation:

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