A teacher is randomly handing out tests. There are 2 different versions of the test, Test A and Test B. If there are 24 tests in all and an equal number of each version, what is the probability that the
first 4 students will all receive Test A?

15/322

Step-by-step explanation:

There are 12 tests of test A, and there are 12 tests of test B.

For the student to get A, it is a 12/24 chance.

For the next student, it is a 11/23 chance

For the next 10/22

For the next 9/21

12/24*11/23*10/22*9/21=15/322

15/322 chance

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .

the answer to the expression is 83