Find the equation of the line that contains the point (-1,-7) and is parallel to the line 6x+5y=11. Write the equation in slope-intercept form, if possible.

y=-1.2x-8.2

Step-by-step explanation:

the equation for the slope is mx+b=y so 6x+5y=11 is the same as 5y=11-6x and that is the same as y=11/5-6/5x. we know the slope is -6/5 and so the y intercept of the line is -7+(-6/5)=-8.2. then the answer is y=-1.2x-8.2

y = -6/5x - 41/5

BRAINLIEST, PLEASE!

Step-by-step explanation:

y = 11/5 - 6/5x

slope = -6/5

y = -6/5x + b

(-1, -7)

-7 = 6/5 + b

b = -35/5 - 6/5

b = - 41/5

idc

step-by-step explanation:

idk

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.