A football is kicked up from ground level at an initial upward velocity of 80 ft./s. The equation h=-16t^2 + 80t give the height h of the football after t seconds. What are realistic values for t?

Step-by-step explanation:

Note that the given height equation, which is a quadratic) has a graph that opens downward.  Borrowing the quadratic formula, we find the roots of this equation, that is, the t values at which h(t) = 0:

The coefficients of this equation are a = -16, b = 80 and c = 0.

We need to find the roots of this quadratic.  By the quadratic formula,

      -(80) ±√(80² - 4(-16)(0) )         -80 ± 0

t = = = -5/2 and -5/2 (seconds).

                 2(-16)                               -32

The initial height is 0 at t = 0 seconds and the final height 0 at 5/2 seconds.

46.2+112.3

step-by-step explanation:

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363