A traveller left town A at 6 :30 am and arrived at 3 :42 pm. how long was the journey

Answer

9 hours 12 minutes

Step by step explanation

(3 : 42 + 12:00)PM

= 15:42

15 : 42 - 6 : 30

= 9hrs 12 minutes

Hope it will help you

Explanation:

Let's break the overall duration into these chunks

Let's add up the minutes portions first

30+42 = 72 minutes

This is over 60 minutes, so we'll rewrite it like this

72 min = 60 min + 12 min = 1 hour, 12 min

The "12 min" is part of the final answer.

The "1 hour" will carry over.

The hours portions of 5 and 3 add to 8. Then tack on that 1 extra hour to get 8+1 = 9 hours.

Overall, the journey was 9 hours and 12 minutes

Here's another approach:

The 12 hour time value of 3:42 PM is the same as 1542 in military or 24 hour time format. To convert any PM time to military time, add 12 to the hours portion (so 3+12 = 15 for instance). The minutes stays the same.

Once the PM time value is in military time, we subtract the starting and ending values

1542 - 0630 = 0912

The first part "09" indicates "9 hours". The second part "12" indicates "12 minutes.

We arrive at the same duration of 9 hours and 12 minutes

Side note: This assumes that all of the traveling occurs on the same day.

she played for 18.75 hours.

step-by-step explanation:

if she played 2/4 of a hour on tuesday. and there is 60 minutes in an hour and 60 divided by 4 is 7.5. and she played 2/4 of an hour on thursday then again 60 divided by 4 is 7.5, you add 7.5+7.5=56.25. now you have to do 1/4 of an hour, it equals 3.75. now you have to add them all up. 3.75+7.5+7.5=18.75

i hope this and i hope you get it right. it took me a while to get this done for you. : )

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.