What is the equation of the line that passes through the points( (-6,-5) and(-5, 5)?

y=10x+55

Step-by-step explanation:

First, you need to find the slope.

y2-y1/x2-x1

-5-5/-6+5=-10/-1=10

Now, we substitute one of the points for the values in y=mx+b

y=10x+b

5=10(-5)+b

5=-50+b

55=b

The full equation is y=10x+55

5x+2x=49

7x=49

x=7. 35 apples

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.