Solve the following inequality using both the graphical and algebraic approach: 5 minus x less-than 2 (x minus 3) + 5 Graph A On a coordinate plane, a line goes through (0, 5) and (5, 0). Another line goes through (negative 2, negative 4) and (2, 3). The lines intersect at (2, 3). Graph B On a coordinate plane, a line goes through (0, 0) and (2, negative 6). Another line goes through (0, negative 8) and (2, negative 6). a. x less-than 2 Graph A b. x greater-than 2 Graph A c. x less-than 2 Graph B d. x greater-than 2 Graph B

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

a

step-by-step explanation:

the denominator cannot be the same as one of the factors.

8 denominator times 2 denominator = 16

and 7 numerator time 11 = 77

77/16= 77/16 ( they cannot be further simplified)

“ a line segment that has the endpoints on the circle and passes through the midpoint is called the diameter. the diameter is twice the size of the radius. a line segment that has its endpoints on the circular border but does not pass through the midpoint is called a chord. a circle is the same as 360 small circle up the number 0 . i hope this .