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Mathematics, 13.01.2022 04:30 kodak0531

Solve for fff: f\div -\dfrac{2}{3}= -\dfrac{1}{3}fΓ·βˆ’
3
2

=βˆ’
3
1

f, divided by, minus, start fraction, 2, divided by, 3, end fraction, equals, minus, start fraction, 1, divided by, 3, end fraction
f =\,

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Solve for fff: f\div -\dfrac{2}{3}= -\dfrac{1}{3}fΓ·βˆ’
3
2

=βˆ’
3
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