Given: triangle KLM, KL=LM, m

Approximately 1.2078566715...

Step-by-step explanation:

Very tricky question! Because the picture doesn't seem to be drawn to scale...

With point O being the center of the circle, construct segments KO, LO, and MO, all of them are the radius of the circle, thus, equivalent.

Since KL=LM, then triangle KLM is an isosceles triangle and angle K is equal to angle M.

(Yes that means "measure of angle")

And because both angles K and M are 17 degrees, then angle L must be 146 degrees.

Now, focus on triangle LOK, since KO=LO, triangle LOK is also an isosceles triangle, thus:

(Since half of angle L is 73)

Then m<KOL must be 34 degrees, and m<KOM will be 68 degrees.

After that, we can use the law of cosine to solve for KM:

The only thing that bothers me is angle KOM being 68 degrees because in the figure angle KOM is clearly an obtuse angle.

I hope I am not tripping.

won't that be plagrisim thought?

step-by-step explanation: