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-3 to the square root of 5 times the square root of 20
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Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tauâŤ0tv(Ď) dĎ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equalsâ¤tless than or equalsâ¤startfraction pi over 3 endfraction Ď 3.
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-3 to the square root of 5 times the square root of 20...
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