A circle that lies on the standard (x, y) , coordinate plane has its center at ,(8,-6) and passes through the orgin. what is the area of this circle in square coordinate units?

Area = 314 units^2

Step-by-step explanation:

Use the points (8, -6) and (0,0) to find the radius. You can use the distance formula. But distance formula is derived from Pythagorean theorem. You can see on the graph, if you did a sketch that the triangle formed is a 6,8,10 Pythagorean triple. Any way you calculate it, you will find the radius is 10. Area of a circle is (pi)r^2.

A = pi × 10^2

A = pi × 100

A = 100pi

Area approximately = 100(3.14)

= 314 units^2

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

y=sec x is the correct answer

~batmans wife dun dun