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Mathematics, 09.01.2022 23:30 Molly666

Given: A(2,1), B(0,5), C(-1,2), AB and BC, mpab = 1/2, mpbc = -1/3, midpoint of AB = (1,3), midpoint pf BC = (-1/2, 7/2). Find standard form equation of line perpendicular to BC through the midpoint .
Use the formula m = y-y1/ x-x1

A. -x - 3y = 10
B. -x + 2y = 5
C. -x - 3y = -10

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Given: A(2,1), B(0,5), C(-1,2), AB and BC, mpab = 1/2, mpbc = -1/3, midpoint of AB = (1,3), midpoint...
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