What is the vertex point of y = |x - 2| + 3? Enter your answer as an ordered pair, e. g. (1,2).

Vertex: (2, 3).

Step-by-step explanation:

The general form of an absolute function is given by: y = a|x - h| + k, where:

| a | ⇒ Determines the vertical stretch or compression factor of the function.

(h, k) ⇒ Coordinates of the vertex, which is either the minimum or maximum point on the graph.

x = h ⇒ Axis of symmetry, which is the imaginary vertical line that splits the graph of the function into two symmetrical parts.

Given the absolute value function, y = |x - 2| + 3:

Based on the general form of absolute value functions described in the previous section of this post, y = a|x - h| + k:

We can assume that the value of "a" in the given absolute value function is 1, because if we distribute 1 into the terms inside the bars, "|    |," the constant value of a = 1 will not change the value of those terms.  

In terms of the vertex, it occurs at point, (2, 3), where h = 2, and k = 3.  

Therefore, the vertex of the given absolute value function is (2, 3).

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!