Suppose an employee works 10 hours on a regular holiday; 8 hours on a rest day and another 10 hours on an ordinary day, how much will the employee be paid if his rate is PHP110/hour and he worked for 6 days during the week and he only
worked the required 8 hours for the 3 ordinary days?
1. Basic pay for the 3 days with no overtime:
2. Basic pay plus overtime pay for the ordinary day with 2 hours overtime
3. Basic pay on rest day
4. Basic pay plus 2 hours overtime on a regular holiday
5. Gross weekly pay

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: