Traffic flow at 1st Ave and High St is twice the traffic flow at 2nd ave and central. Compare the graph of the traffic flow at 1st Ave and High St to the graph of the traffic flow at 2nd Ave and Central over time

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

5050 i think

step-by-step explanation:

answer: y=4000x+14000

step-by-step explanation:

answer: your gay

step-by-step explanation:

you dont know math