How to factorise:

1) 9t²w - 3.

2) 4(x - 5)² + 3 (x - 5)

1.  

2.  

Step-by-step explanation:

For the first question, you simply get the common factor out of both values and in this case it is 3. So if you take 3 out of it is basically like dividing.

*You can't divide the alphabetic variables though* So it would be 3t^2w

Then, with -3 you again divide it by 3 so it would be -1.

Put them together and you get

3(3t^2w-1)

For the second question it has some more steps than the first one.

You first expand both of them:

4(x-5)(x-5) + 3x - 15

Then you should expand the double brackets using the foil method ( search it up if confused):

Then you simply the brackets where -5x and -5x makes -10x. Now take the whole bracket and times it by 4 :

Now you simplify again:

You then factorise this equation right here into a double bracket:

As you could see (x-5) is the same so it works!

then you factorise it to:

I hope it is right and if you see any mistakes pls feel free to ask :)

32

step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl