![f(x) = \sqrt[3]{x + 2} \\ \\ f(25) = \sqrt[3]{25 + 2} = \sqrt[3]{27} = 3 \\ \\ f( - 66) = \sqrt[3]{ - 66 + 2} = \sqrt[3]{ - 64} = - 4](/tpl/images/2610/0080/da434.png)
Math
need help!!
f(25)= ?
f(-66)= ?
...
Answers: 1
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