What is an equation of the line that passes through the points (−6,−2) and (6,8)?

y = 10/12 + 2

Step-by-step explanation:

 Start by knowing that you have to know y = mx + b. If you don't you can't answer. So first you have to take the two coordinates and do rise over run.

      -2 is a y coordinate and 8 i also a y, so we do this, 8 - - 2, which is 8 + 2. After that you should get 10, now do the other ones, 6 - - 6 = 6 + 6 = 12. A thing to be wary of is to now switch what you add or subtract, you cant start with one coordinate and stop with another. For example we first subtracted from 8, then we subtracted from 6. If we would have subtracted from 8 then -6 the equation would be wrong.  now we have the slope, which is M in y = mx + b. he slope is rise over run ( rise/run or y/x)  to get the b you have to substitute the slope into the equation so, y = 10/12x + b. Now just grab a coordinate and sub it into the equation so, 8 = 10/12*6 +b. now we do the equation, now we have 8 = 5 + ?, simple, if it wasn't we would have to subtract 8 from 5, so 8 - 5 = 2. That would show 2 = ?. We finally have the answer y = 10/12 + 2

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.