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Mathematics, 03.01.2022 01:20 ayoismeisalex

g(x)=βˆ’20βˆ’3x h(x)=( 2 1 ) x Evaluate. (g\circ h) (-2)=(g∘h)(βˆ’2)=left parenthesis, g, circle, h, right parenthesis, left parenthesis, minus, 2, right parenthesis, equals

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g(x)=βˆ’20βˆ’3x h(x)=( 2 1 ) x Evaluate. (g\circ h) (-2)=(g∘h)(βˆ’2)=left parenthesis, g, circle, h, rig...
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