Flying against the wind, an airplane travels 2700 kilometers in 5 hours. Flying with the wind, the same plane travels 3600 kilometers in 4 hours. What is the rate of the plane in still air and what rate of the wind

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

step-by-step explanation:

what is the figure? attach a picture.

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