A bag contains one red pen, four black pens, and three blue pens. Two pens are randomly chosen from the bag and are not replaced. To the nearest hundredth, what is the probability that a black pen is chosen first and then another black pen is chosen?.

3/14

Step-by-step explanation:

total pens = one + four + three = 1 + 4 + 3 = 8

there are 4 black pens

probability a black pen is chosen randomly: 4/8 (number of outcomes/total outcomes) = 1/2

take the pen out

there are now 3 black pens and 8-1 = 7 total pens

probability a black pen is now chosen: 3/7

we want to find the probability that the black pen is chosen first AND second at random.

P(A and B) = P(A) * P(B)

multiply the 2 probabilities to get our solution

1/2 * 3/7 = 3/14

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation:

where are the graphs?

step-by-step explanation: