use the given transformation to evaluate the integral. 2y2 da, r where r is the region bounded by the curves xy = 2, xy = 4, xy2 = 2 and xy2 = 4; u = xy, v = xy2

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )