Twice a number x excced 5 by at least 4, find all possible value of X

x > 4.5

Step-by-step explanation:

Twice a number x = 2 * x

must exceed 5 by at least 4 = 2 * x > 5 by at least 4 = 2* x > 5 + 4

Twice a number x (2*x) must exceed 5 (>5) by at least 4 (+4)

2* x > 5 + 4

2x > 9

divide both sides by 2 to isolate x

x > 4.5

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions

b, i believe, but not sure.