The brother is 5 years older than Sister. Find the sum of siblings's ages if their ages 4 years ago were the same as 3: 2.

the sum of siblings' ages is 25 years

Solution given:

let the age of brother be x and sister age be y.

By question at the present age of the brother is 5 years older than his sister. in the equation,

it can be  written as:

x=y+5[1]

again;

Before 4 years

sister's age will be y-4.

brother's age will be y-4+5=y+1

Since their ages 4 years ago were the same as 3: 2.

so according to the question.

3(y-4)=2(y+1)

solving the equation, we get

3y-12=2y=2

3y-2y=2+12

y=14

Before 4 years ago the age of sister is y=14-4=10 years

and the present age of brother is x=y+5=10+5=15 years

now

the sum of siblings' ages=x+y=10+15=25 years

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.

it’s the first one your welcome