Find the centroid of the triangle whose vertices are the points A (8 , 4) B (1 , 3) and C (3 , -1). If the two lines are perpendicular with the slopes m1 and m2 then m1 ⋅ m2 =

#Find the centroid of the triangle whose vertices are the points A (8 , 4) B (1 , 3) and C (3 , -1).

#Centroid of the triangle = (x1 +x2 + x3)/3, (y1+y2+y3)/3

= (8+1+3)/3, (4+3-1)/3

= 12/3, 6/3

= (4, 2)

So, the centroid of the triangle is (4, 2).

If the two lines are perpendicular with the slopes m1 and m2 then m1 ⋅ m2 =

If two lines are perpendicular, then the product of their slopes will be equal to -1.

Step-by-step explanation:

#itzuryesul

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23

no

step-by-step explanation:

answer