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Mathematics, 25.12.2021 19:50 HopeDied

Cos²θ⋅sin⁴θ=1/32 (2−cos2θ−2cos4θ+cos6θ)


Cos²θ⋅sin⁴θ=1/32 (2−cos2θ−2cos4θ+cos6θ)

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Cos²θ⋅sin⁴θ=1/32 (2−cos2θ−2cos4θ+cos6θ)
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