3. Write the equation of the altitude from B for A(-7,-5) B(-5,5), C(2, 1).

  y -5 = -3/2(x +5)

Step-by-step explanation:

The altitude from B is perpendicular to segment AC. The slope of segment AC is ...

  m = (y2 -y1)/(x2 -x1)

  m = (1 -(-5))/(2 -(-7)) = 6/9 = 2/3

The slope of the altitude line will be the opposite reciprocal of this, so is ...

  -1/m = -1/(2/3) = -3/2

The point-slope form of the equation of a line is ...

  y -k = m(x -h) . . . . . . line with slope m through point (h, k)

  y -5 = -3/2(x +5) . . . . . line with slope -3/2 through B(-5, 5)

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Additional comment

The equation can be put in other forms, as you may wish. Solving for y gives the slope-intercept form.

  y = -3/2x -5/2 . . . . . slope-intercept form

 3x +2y = -5 . . . . . . . standard form

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

i believe the correct answer is b.