All the stores in Quartz EXCEPT the Quartz Emporium have released their available 2020 sales data. From this, the Watch Dogs were able to ascertain that the least mean amount spent per shopping trips among all the other stores was $23.00. Consequently, even if the Watch Dogs reject the null hypothesis that the mean amount spent per shopping trip at the Quartz Emporium is $22.50 but only show it is some value less than $23, they cannot claim false advertising as the Quartz Emporium would still be the cheapest in town. Assume the population standard deviation of the amount spent per shopping trip at the Quartz Emporium is currently $16.00. 1) Towards the prior goal, the WatchDogs are going to reperform the same hypothesis test at level of significance do = 0.05, using a newly collected sample of size n = 50. How likely are they to come to the correct conclusion to reject the null hypothesis if in fact the mean amount spent per shopping trip at the Quartz Emporium is $23.00? - 2 pts 2) What is the probability the Watch Dogs could come to the erroneous conclusion to accept the null hypothesis at level of significance do = 0.05, using a newly collected sample of size n = 50, if in fact the mean amount spent for shopping trip at the Quartz Emporium is $23.00? - pt 3) If the WatchDogs wish to reperform the same hypothesis test at level of significance do = 0.05 and be 80% certain they to come to the correct conclusion to reject the null hypothesis when in fact the mean amount spent for shopping trip at the Quartz Emporium is $23.00, how many shoppers from the Quartz Emporium should they survey?