Solve the quadratic by factoring. 5x^2+3x+9=-10+3

No real solutions

Step-by-step explanation:

First, set it to equal to zero.

5x2−3x=−8

5x2−3x+8=0

If factoring the quadratic equation doesn't solve the

problem, use the quadratic formula as a last resort to find

xx=−b±√b2−4ac2a when a=5,b=−3,c=8

x=−(−3)±√(−3)2−4(5)(8)2(5)=3±√9−16010

Now if you look at the discriminant which is b2−4ac, is negative. The discriminant tells you how many real solutions are in the equation.

remember this:

when b2−4ac<0 is negative , there are no real solutions

when b2−4ac=0 is zero, there is one real solution

when b2−4ac>0 is positive, there are two real solutions

so the answer is that there are no real solutions

just needed some points but try socratic

if you was gonna solve for a, a is a   < -12