What is the 100th term of sequence for -25,-13,1,11

The 100th term i 1163

Step-by-step explanation:

From -25 to -13 is a positive jump of 12, and

from -13 to 1 is a positive jump of 14, and

from 1 to 11 is a positive jump of 10

So there's something wrong with the given sequence  Let's assume that the sequence is actually -25, -13, -1, 11.  There's always a positive jump of 12 from one term to the following term.

Regard this as an arithemeti sequence with first term -25 and common difference (d) = 12.

Then the general formula for this sequence is a(n) = a(1) + d(n - 1).  For the given situation, it becomes a(n) = -25 + 12(n - 1), and for a(100) we have

a(100) = -25 + 12(100 - 1), or

a(1000 = -25 + 12(99) = 1163

The 100th term is 1163

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.