What is the solution to the following system of equations? −x−2y−4z=−6
x−5y−2z=−2
2x−3y+2z=2

y=-3

Step-by-step explanation:

[1]    x = 2y + 4z + 26

// Plug this in for variable  x  in equation [2]

  [2]    4•(2y+4z+26) - 2y + 4z = 6

  [2]    6y + 20z = -98

// Plug this in for variable  x  in equation [3]

  [3]    2•(2y+4z+26) + 2y - z = 6

  [3]    6y + 7z = -46

// Solve equation [3] for the variable  z

 [3]    7z = -6y - 46

 [3]    z = -6y/7 - 46/7

// Plug this in for variable  z  in equation [2]

  [2]    6y + 20•(-6y/7-46/7) = -98

  [2]     - 78y/7 = 234/7

  [2]     - 78y = 234

// Solve equation [2] for the variable  y

[2]    78y = - 234

  [2]    y = - 3

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column