What is the answer for this 2q+10=7q

q=2

Step-by-step explanation:

2q + 10-10= 7q

2q + 10-10 = 7q- 10

Simplify:

2q= 7q - 10

Subtract 7 q from both sides of the equation:

2q= 7q - 10

2q- 7q =7q- 10-7q

-5q= -10

Divide both sides of the equation by the same term:

-5q= -10

-5q/-5= -10/-5

Cancel terms that are in both the numerator and denominator:

q= -10/-5

Divide the numbers:

q= -10/-5

q=2

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

true

step-by-step explanation: