Enter a number in each blank M(x)=(2x-6)(x-4) true statements when M(x)=0 when x=

22345

Step-by-step explanation:

{3, 4}

Step-by-step explanation:

"M(x)=(2x-6)(x-4) true statements when M(x)=0 when x= ?" asks us to find the "roots" of M(x); that is, the x values at which M(x) = 0.  Thus, we set

(2x - 6)(x - 4) = 0, which is equivalent to 2(x - 3)(x - 4) = 0.

Thus, x - 3 = and x = 3; also x - 4 = 0, so that x = 4.  

The roots of M(x) are {3, 4}

Using the language of the original problem:  "true statements when M(x)=0 when x="              the correct results, inserted into the blanks, are x = 3 and x = 4.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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