The largest lollipop ever made had a mass of 2158.7kg and was made for a festival in Granna, Sweden on July 27, 2003, If a spherical lollipop with radius 2 cm has a mass of 50 g, what was the radius of this giant lollipop?

Step-by-step explanation:

Assuming the density is the same for both lollipops, we can calculate what volume is required to make the 2158.7kg the same density of the smaller lollipop.  

Small Lollipop

r = 2cm

V=4 /3πr^3

V = 33.51 cm^3

Mass is 50 g in 33.51 cm^3, so the density is:

50g/(33.51 cm^3) = 1.492 g/cm^3

We have 2158.7kg in the larger lollipop.  That is 2158700 grams.

Find the volume required to contain 2158700 grams with a density of 1.492 g/cm^3.  :

       (2158700 grams)/(1.492 g/cm^3) = 1446775 cm^3

V=4 /3πr^3

1446775 cm^3 = (4/3)*π*r^3

r = 70.12 cm

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it