Suppose we want to classify defects found in furniture produced in a manufacturing plant according to (1) the type of defect and (2) the production shift. A total of 309 furniture defects were recorded as one of four types, A, B, C, or D. At the same time each piece of furniture was identified according to the production shift during which it was manufactured, 1st shift, 2nd shift, or 3rd shift. What degrees of freedom should be used to calculate a p-value in a Chi-Squared test for independence between the type of defect and production shift?

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

can i see the following ?

step-by-step explanation:

40 x 50 = 2000

step-by-step explanation:

it would take 5 hours i think idk i'm not that good at math.can you me with my questions i need asap.