Jovie is maintaining a camp fire. She has kept the fire steadily burning for 101010 hours with 151515 logs. She wants to know how many hours (h)(h)left parenthesis, h, right parenthesis she could have kept the fire going with 9 logs. She assumes all logs are the same. How many hours can Jovie keep the fire going with 9 logs?

Step-by-step explanation:

101010:151515 is the same as 2:3 or 2 logs for 3 hours. Using that you can set up your equation as such:

2:3

x:9

And then multiply across:

2x9 = 3x

18/3 = x

6 = x

Jovie can keep the fire running for 6 hours with 9 logs.

Another way to do this is to divide the log numbers, 9/3 = 3, and then multiply the hours by this number, 2x3 = 6.

Hope that helps

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363

answer: 0.26

i used the calculator on google