1. Given that z is the standard normal variable (with mean 0 and standard deviation 1), find
(a) P(0 = z = 1.75) (b) P(-1.29 = 2 = 0)
(c) P(1.03 = z = 1.21) (d) P(z = 2.31)
(e) P(Z < -1.96)
(f) P(z = 1.00)

after simplifying it i got: -36.25 as my answer. hope that !

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

we are given expression: and .

in order to find it's greatest common factor, let us break it into smaller parts.

let us find greatest common factor of 54 and 27 first.

54 = 27 × 2

27 = 27 × 1

now, let us find the greatest common factor of m and m^3.

now, let us find the greatest common factor of n^4 and n^2.

therefore, following expressions are part of the greatest common factor of 54mn^4 and 27m^3n^2.