A skydiver jumps from a plane with an initial height of 13739 feet and an initial velocity of -1 feet per second. For a safe landing, the skydiver wants to pull their parachute between 6000 feet and 2000 feet above the ground. During what interval of time should the skydiver pull their parachute, to the nearest hundredth?

step- i d k and i d c : )

you: : 0

bye

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58

im super bad at school but u for some reason need to have points to ask questions and you get points by answering so thats all im doing sorry for t r o l l i n g  

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