If \sin A = \frac{12}{13}sinA= 13
12

and \cos B=\frac{11}{61}cosB=
61
11

and angles A and B are in Quadrant I, find the value of \tan(A+B)tan(A+B).

the answer i believe is 27 units.

step-by-step explanation:

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.

no its the same as every other grade

step-by-step explanation: