Write the equation of the line that is perpendicular to y=3x-6 and passes through the point x, y
(2,0)

Perpendicular is the negative reciprocal so the slope is -1/3

Need to know b and the full equation

With work please. Thank you!

y=-1/3x+2/3 (please mark brainliest)

Step-by-step explanation:

start with y=3x+6

you can get the slope of the perpendicular line by dividing the slope by -1,

so the slope of the new line is -1/3.

using the point and the slope of the new line, we can put it into point-slope form:

y-y₁=m(x-x₁)

y-0=-1/3(x-2)

simplify:

y=-1/3x+2/3

this is the final equation in the form y=mx+b

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.