What is the probability of rolling a number less than or equal to eight with the sum of two dice, given that at least one of the dice must show a 6?

4/11

Step-by-step explanation:

Outcomes that meet your requirement are

 (1, 6), (2, 6), (6, 1), (6, 2)

for a total of 4 favorable outcomes.

There are 11 outcomes in which one die shows a 6.

So your probability would be 4/11.

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2