Determine a series of transformations that would map polygon ABCD onto polygon A'B'C'D'?
y
12
11
10
9
8
. Na 000
7
6
5
ch
C
B'
D'
1
-12-11-10-9-8-7-6-5-4-3-2-13
1 2 3 4 5 6 7 8 9 10 11 12
-2
-3
-4
-5
-6
B
A
17
7
-8
O 005 och
D
-9
-10

answer is x<

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

all you have to do is multiply them both to see how many out comes you can put:

3 x 2 = 6

you can make 6 diferent combinations of crusts and toppings.

~batmans wife dun dun