What is the standard form of the parabola whose vertex form is y= 2(x+4)^2+5 A. y = 2x2 +16x - 37
B. y=-2x² + 4x - 25
C. y = 2x° +16x +37
D. y = 2x² + 4x - 25

tube or goog would be a great resource to with that question

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

the surface area is 124cm²

step-by-step explanation:

length: 4cm

width: 9cm

height:   2cm

step-by-step explanation: