subject
Mathematics, 07.12.2021 23:20 7431335

Treatment providers for problem gamblers report that men who approached them for intervention had lost a mean of $2,849 in the preceding four weeks, according to a 2002 report. Assume that the distribution of gambling losses is normally distributed with a mean of $2,849 and a standard deviation of $900. We would expect to see 95% of the number of gambling losses to be between what two values? A.
1049 and 4649

B.
1949 and 3749

C.
149 and 5549

D.
There is not enough information to tell in this case.

ansver
Answers: 2

Another question on Mathematics

question
Mathematics, 21.06.2019 16:30
The ratio of men to women working for a company is 4 to 5 . if there are 90 women working for the company, what is the total number of employees?
Answers: 1
question
Mathematics, 21.06.2019 18:30
Express the following as a function of a single angle. cos(60) cos(-20) - sin(60) sin(-20)
Answers: 1
question
Mathematics, 21.06.2019 18:40
Solve the equation below: (x+4)/6x=1/x a. x=2 b. x=0,2 c. x=-2 d. x=0,-2
Answers: 1
question
Mathematics, 21.06.2019 19:00
Write the pair of fractions as a pair of fractions with a common denominator
Answers: 3
You know the right answer?
Treatment providers for problem gamblers report that men who approached them for intervention had lo...
Questions
question
Biology, 16.04.2021 01:00
question
English, 16.04.2021 01:00
question
Mathematics, 16.04.2021 01:00