Mathematics, 07.12.2021 18:50 terabear2033
Please help me solve these problems
tanA - secA =
1. (SinA - 1)/ CosA
2. (Sin²A - CosA)/ CosA
3. (Cos²A - 1)/ CosA
cos B cot B - tan B =
1. (Cos²B - SinB)/ SinB CosB
2. (Sin²B - CosB)/ SinB
3. (Cos³B - Sin²B)/ SinB CosB
sec B cot B =
1. cosB/sin²B
2. 1/sinB
3. sinB/cos²B
Answers: 1
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Please help me solve these problems
tanA - secA =
1. (SinA - 1)/ CosA
2. (Si...
1. (SinA - 1)/ CosA
2. (Si...
Mathematics, 20.06.2020 00:57