Hi I need help with this thx A water tank fills through two pipes. Water flows through
one pipe at a rate of 25,000 gallons an hour and through
the other pipe at 45,000 gallons an hour. Water leaves the
system at a rate of 60,000 gallons an hour.

There are 3 of these tanks, and each tank holds 1 million
gallons. Each tank is half full. Water is entering and
leaving a tank at the maximum amounts. Determine the
number of hours, x, it will take to fill all 3 tanks.

answer: the answer is fre sha voca do

step-by-step explanation:

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

the ratios are reciprocals im positive

step-by-step explanation:

they are all positive numbers so it wouldn't be the other ones