The set of all polynomials of degree 6 under the standard addition and scalar multiplication operations is not a vector
space because *
O We can find two polynomials P(x) and Q(x) for which P(x).Q(x)#Q(x)=P(x)
O It is not closed under addition.
O We can find a polynomial P(x) such that (c+d)P(x)+cP(x)+dP(x).
O We can find a polynomial P(x) for which 1.P(x)#P()

Step-by-step explanation:

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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