Packs of collectible cards claim that 1 out of 3 packs contains a rare card.
Margie bought 7 packs and only
received a rare card in 1 of the packs.
Number of packs with
a rare card
Frequency
0
6
1
20
2
31
3
26
Margie runs a simulation of 100 trials. In
the simulation, she used a random
number generator to select 7 digits
from 1 to 3 with 1 representing a pack
with a rare card and 2 and 3
representing a pack without a rare card.
The frequency of the number of packs
with rare cards in each trial of 7
samples in the simulation is
represented by this table.
4
13
5
4
6
0
7
0
What is the best conclusion for Margie
to make based on the data?

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

im not sure what this means: mc011-7.jpg

step-by-step explanation:

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x