Use the rules of exponents to simplify the expression. write the answer with positive exponents. Assume that all variables represent positive real numbers.

I don't understand,

Step-by-step explanation:

is it true ? first we want to simplify the expression in the numerator. Since the term (x2z) is being raised to the 1/4 power, we multiply the exponents of each variable to give us a simplified power. The denominator is already simplified. This gives us

x2*1/4z1/4/x-1/2z1/2

x1/2z1/4/x-1/2z1/2

To further simplify from this point, we make use of the fact that xA/xB=xA-B. That is, the power of exponential terms divided by terms with the same base is equal to the difference in the exponents. We do this for both x and z.

x1/2-(-1/2)z1/4-1/2

We recognize that the subtraction of a negative term in a power of x leads us to add the two terms, and we find a common denominator, 4, to subtract the powers of z. We find

x1z-1/4

The power of 1 in the x term gives us our base, x, and the power of -1/4 in the z term can be rewritten as a positive exponent in the denominator of our simplified expression. This gives the answer

x/z1/4

the dimensions are:

step-by-step explanation:

we want to find the dimensions of a rectangular box with volume of

we factor to obtain;

we rewrite the rightmost factor to obtain;

recall that:

we apply difference of two squares formula to obtain;

hence the dimensions are

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.