The swan below is composed several triangles. Use the given information and the figure to find each angle measure. Note: Figure not drawn to scale.
Given: ABC is equilateral; ZBCD = LBDC; DE = CE = EF; LCGF = ZCFG;
AGCF = AGKF = JHM; AKFH = AKLH; KOFO;
ZHKN = HNK; IN JO
B
(4x)
А
02
(7x)
D
C
(47)
(62)
(32)
E
(102)
(2z + 6)
G
(167)
H
1
(8x + 2)°
(47)
(4z - 7)"
K
M
(x + 6)
(8y)
o
N
1. MLABC
2. m2 BCA
3. MZ CAB
4. mZBCD
5. MBDC
6. mZCBD
7. mZEDC
8. MZECD
9. mZCED
10. mZECF
11. mZEFC
12. mZCEF
13. mZCGF
14. mZCFG
15. mZGCF
16. MZKGF
17. m2 KFG
18. MZGKF
19. mZFKH
20. mZFHK
21. mZKFH
22. m2KHL
23. MZHKL
24. m2 KLH
25. mZHJM
26. mZHM)
27. mZJHM
29. mZOKF
28. mZOFK
30. mZKOF
31. mZHKN
33. mZOKN
32. mZHNK
34. mLJNO
35. MZJON
36. mZNJO

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

true !

step-by-step explanation:

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.

∠cbe and ∠deb are same-side interior angles.

i took the test